LED Design Info
#21
just cheat and do this, its much easier... but its best to know how to do it case your in the desert w/ out a wifi connection and your phone dosent get any reception.
http://led.linear1.org/led.wiz
http://led.linear1.org/led.wiz
#27
i just looked it up and this is the info i recieved:
Solution 0: 6 x 1 array uses 6 LEDs exactly________R
(+)----|>|----|>|----|>|----|>|----|>|----|>|---/\/\/----(-)
R = 1 ohms
The wizard says: In solution 0:
each 1 ohm resistor dissipates 0.4 mW
the wizard thinks ¼W resistors are fine for your application
together, all resistors dissipate 0.4 mW
together, the diodes dissipate 240 mW
total power dissipated by the array is 240.4 mW
the array draws current of 20 mA from the source.
now i thought you said that i should put the Resistor on the (+)-side...this is showing it on the (-)-side (ground)...either way makes senses to me but i want to know what you guys think is the best....
Solution 0: 6 x 1 array uses 6 LEDs exactly________R
(+)----|>|----|>|----|>|----|>|----|>|----|>|---/\/\/----(-)
R = 1 ohms
The wizard says: In solution 0:
each 1 ohm resistor dissipates 0.4 mW
the wizard thinks ¼W resistors are fine for your application
together, all resistors dissipate 0.4 mW
together, the diodes dissipate 240 mW
total power dissipated by the array is 240.4 mW
the array draws current of 20 mA from the source.
now i thought you said that i should put the Resistor on the (+)-side...this is showing it on the (-)-side (ground)...either way makes senses to me but i want to know what you guys think is the best....
#28
It doesnt matter which side the resistor goes on.
I prefer to avoid laying the circuits out so that you need such a low resistance. When you are using a 1 ohm resistor, it doesnt take much of a resistance or load variation in the rest of the circuit to influence the brightness of the leds. This is due to the fact that even a small amount of resistance change in the circuit will be a significant percentage of the limiting resistor.
If you are running of of 12V and use 6 leds in series, you will not have enough current even with no load resistance if you use white, blue or supergreen leds (3Vf each). If you use red, amber, or another 2V led you would need the super low resistance.. probably what that calculator was figuring.
I would recommend making 2 series circuits with 3 leds each. If you use blue, white or green (3V) leds, then you could place a 200 ohm resistor in series with each branch and have approx. 15ma through each one. 150ohms or so get you 20ma. If you were running 2V leds (like red) then you would use about 400 ohms for each branch to draw 15ma.
I prefer to avoid laying the circuits out so that you need such a low resistance. When you are using a 1 ohm resistor, it doesnt take much of a resistance or load variation in the rest of the circuit to influence the brightness of the leds. This is due to the fact that even a small amount of resistance change in the circuit will be a significant percentage of the limiting resistor.
If you are running of of 12V and use 6 leds in series, you will not have enough current even with no load resistance if you use white, blue or supergreen leds (3Vf each). If you use red, amber, or another 2V led you would need the super low resistance.. probably what that calculator was figuring.
I would recommend making 2 series circuits with 3 leds each. If you use blue, white or green (3V) leds, then you could place a 200 ohm resistor in series with each branch and have approx. 15ma through each one. 150ohms or so get you 20ma. If you were running 2V leds (like red) then you would use about 400 ohms for each branch to draw 15ma.
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